NCERT Class XI Mathematics - Statistics - Solutions

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Question : 30
Total: 34
The mean and standard deviation of six observations are 8 and 4, respectively. If each observation is multiplied by 3, find the new mean and new standard deviation of the resulting observations.
Solution:  
Let x1,x2,x3,x4,x5,x6 be the six observations, then
x1+x2+x3+x4+x5+x6
6
= 8
x1+x2+x3+x4+x5+x6 = 48
Now if each observation is multiplied by 3 then
New mean =
3x1+3x2+3x3+3x4+3x5+3x6
6

=
3(x1+x2+x3+x4+x5+x6)
6
=
1
2
× 48 = 24
Also ,
1
6
(x12+x22+x32+x42+x52+x62)
(8)2
= 16
x12+x22+x32+x42+x52+x62 = 480
If each observation is multiplied by 3, then
New variance
=
1
6
(9x12+9x22+9x32+9x42+9x52+9x62)
(24)2

=
9
6
× 480 - 576 = 720 - 576 = 144
∴ New S.D. = 144 = 12
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