NCERT Class XI Mathematics - Straight Lines - Solutions
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Question : 35
Total: 74
Reduce the following equations into slope-intercept form and find their slopes and the y-intercepts.
(i) x + 7y = 0,
(ii) 6x + 3y –5 = 0,
(iii) y = 0
(i) x + 7y = 0,
(ii) 6x + 3y –5 = 0,
(iii) y = 0
Solution:
(i) We have given an equation x + 7y = 0, which can be written in the form
⇒ 7y = - x ⇒ y =−
x + 0 ... (1)
Also, the slope intercept form is y = mx + c ... (2)
On comparing (1) and (2), we get m =−
, c = 0
Hence the slope is−
and the y-intercept = 0.
(ii) We have given an equation 6x + 3y – 5 = 0, which can be written in the form 3y = – 6x + 5 ⇒ y = − 2x +
... (1)
Also, the slope intercept form is y = mx + c ... (2)
On comparing (1) and (2), we get m = − 2 and c =
i.e. slope = – 2 and the y-intercept =
(iii) We have given an equation y = 0
⇒ y = 0.x + 0 ... (1)
Also, the slope intercept form is y = mx + c ... (2)
On comparing (1) and (2), we get m = 0, c = 0.
Hence, slope is 0 and the y-intercept is 0.
⇒ 7y = - x ⇒ y =
Also, the slope intercept form is y = mx + c ... (2)
On comparing (1) and (2), we get m =
Hence the slope is
(ii) We have given an equation 6x + 3y – 5 = 0, which can be written in the form 3y = – 6x + 5 ⇒ y = − 2x +
Also, the slope intercept form is y = mx + c ... (2)
On comparing (1) and (2), we get m = − 2 and c =
i.e. slope = – 2 and the y-intercept =
(iii) We have given an equation y = 0
⇒ y = 0.x + 0 ... (1)
Also, the slope intercept form is y = mx + c ... (2)
On comparing (1) and (2), we get m = 0, c = 0.
Hence, slope is 0 and the y-intercept is 0.
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