(i) Given equation is 3x + 2y – 12 = 0
We have to reduce the given equation into intercept form, i.e.,

x

a

+

y

b

= 1 ... (1)
Now given, 3x + 2y = 12
⇒

3x

12

+

2y

12

= 1 ⇒

x

4

+

y

6

= 1 ... (2)
On comparing (1) and (2), we get a = 4, b = 6
Hence, the intercepts of the line are 4 and 6.
(ii) Given equation is 4x – 3y = 6
We have to reduce the given equation into intercept form, i.e.,

x

a

+

y

b

= 1 ... (1)

4

6

x−

3

6

y = 1 or

x

3 2

+

y

−2

= 1 ... (2)
On comparing (1) and (2), we get a =

3

2

and b = - 2
Hence, the intercepts of the line are

3

2

and - 2
iii) Given equation is 3y + 2 = 0
We have to reduce the given equation into intercept form, i.e.,

x

a

+

y

b

= 1
3y = - 2 ⇒ y = −

2

3

The above equation shows that, it is not the required equation of the intercept form as it is parallel to x-axis.
We observe that y-intercept of the line is −

2

3

, but there is no intercept on x-axis.