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NCERT Class XI Mathematics - Straight Lines - Solutions

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Question : 60
Total: 74
Find the equation of a line drawn perpendicular to the line
x
4
+
y
6
 = 1 through the point, where it meets the y-axis.
Solution:  
We have,
x
4
+
y
6
 = 1 ... (i)
Now slope of (i) = −
3
2
slope of any line perpendicular to line (i) meets the y-axis at (0, 6) is
2
3
.
∴ Equation of the line through (0, 6) and perpendicular to line (i) is
(y - 6) =
2
3
 (x - 0) ⇒ 3y = - 18 = 2x ⇒ 2x - 3y + 18 = 0.
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