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NCERT Class XI Mathematics - Trigonometric Functions - Solutions

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Question : 19
Total: 61
2sin2
π
6
+cosex2
7π
6
cos2
π
3
 =
3
2
Solution:  
L..S = 2sin2
π
6
+cosex2
7π
6
cos2
π
3
= 2 ×
1
4
 + (cosec2(π+
π
6
))(
1
2
)2 =
1
2
+(−2)2×
1
4
 =
1
2
+1 =
3
2
 = R.H.S.
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