NCERT Class XI Mathematics - Trigonometric Functions - Solutions

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Question : 32
Total: 61
cot 4x (sin 5x + sin 3x) = cot x (sin 5x – sin 3x)
Solution:  
We have, L.H.S. = cot 4x (sin 5x + sin 3x)
= cot 4x × 2 sin (
5x+3x
2
)
cos (
5x3x
2
)

=
cos4x
sin4x
× 2 sin 4x cos x = 2 cos 4x cos x ... (i)
And, R.H.S.= cot x (sin 5x – sin 3x)
= cot x × 2 sin (
5x3x
2
)
cos (
5x+3x
2
)

=
cosx
sinx
× 2 sin x cos 4x = 2 cos 4x cos x ... (ii)
From (i) & (ii), we get L.H.S.= R.H.S.
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