NCERT Class XI Mathematics - Trigonometric Functions - Solutions
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Question : 32
Total: 61
cot 4x (sin 5x + sin 3x) = cot x (sin 5x – sin 3x)
Solution:
We have, L.H.S. = cot 4x (sin 5x + sin 3x)
= cot 4x × 2 sin(
) cos (
)
=
× 2 sin 4x cos x = 2 cos 4x cos x ... (i)
And, R.H.S.= cot x (sin 5x – sin 3x)
= cot x × 2 sin(
) cos (
)
=
× 2 sin x cos 4x = 2 cos 4x cos x ... (ii)
From (i) & (ii), we get L.H.S.= R.H.S.
= cot 4x × 2 sin
=
And, R.H.S.= cot x (sin 5x – sin 3x)
= cot x × 2 sin
=
From (i) & (ii), we get L.H.S.= R.H.S.
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