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Kinetic Theory

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Question : 12
Total: 14
From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7cm3s−1. The diffusion of another gas under the same conditions is measured to have an average rate of 7.2cm3s−1. Identify the gas.
Solution:  
According to Graham’s law of diffusion,
r1
r2
=√
M2
M1
where, r1=diffusion rate of hydrogen =28.7cm3s−1
r2= diffusion rate of unknown gas =7.2cm3s–1
M1= molecular mass of hydrogen =2u

M2=?
∴
28.7
7.2
=√
M2
2
 or M2=(
28.7
7.2
)2×2 =31.78≈32
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