Kinetic Theory
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Question : 13
Total: 14
A gas in equilibrium has uniform density and pressure throughout its volume. This is strictly true only if there are no external influences. A gas column under gravity, for example, does not have uniform density (and pressure). As you might expect, its density decreases with height. The precise dependence is given by the so-called law of atmospheres
n 2 = n 1 exp [ − m g
]
wheren 2 , n 1 refer to number density at heights h 2 and h 1 respectively. Use this relation to derive the equation for sedimentation equilibrium of a suspension in a liquid column : n 2 = n 1 exp [ − m g N A ( ρ − ρ )
] . where r is the density of the suspended particle, and ρ′ that of surrounding medium.
[N A is Avogadro’s number, and R is the universal gas constant.]
where
[
Solution:
According to the law of atmospheres,
n 2 = n 1 exp . [ −
( h 2 − h 1 ) ] ... (i)
wheren 2 , n 1 refer to number density of particles at heights h 2 and h 1 respectively.
If we consider the sedimentation equilibrium of suspended particles in a liquid, then in place of mg, we will have to take effective weight of the suspended particles.
Let V = average volume of a suspended particle, r = density of suspended particle,
r′ = density of liquid, m = mass of equal volume of liquid displaced.
According to Archimede’s principle, effective weight of one suspended particle = actual weight – weight of liquid displaced= m g − m ′ g = m g − V ρ ′ g = m g − (
) ρ ′ g = m g ( 1 −
) Also, Boltzman constant, k B =
where, R is gas constant andN A is Avogadro’s number.
Putting,m g ( 1 −
) in place of m g and value of k B in (i), we get n 2 = n 1 exp . [ −
( 1 −
) ( h 2 − h 1 ) ] which is the required relation.
where
If we consider the sedimentation equilibrium of suspended particles in a liquid, then in place of mg, we will have to take effective weight of the suspended particles.
Let V = average volume of a suspended particle, r = density of suspended particle,
r′ = density of liquid, m = mass of equal volume of liquid displaced.
According to Archimede’s principle, effective weight of one suspended particle = actual weight – weight of liquid displaced
where, R is gas constant and
Putting,
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