Laws of Motion
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Question : 18
Total: 40
Two billiard balls each of mass 0.05 kg moving in opposite directions with speed 6 m s– 1 collide and rebound with the same speed. What is the impulse imparted to each ball due to the other?
Solution:
Let the two balls A and B moving in opposite directions collide and rebound with same speed.
Initial momentum of the ball A = 0.05 × (6) = 0.3 kg m s– 1
Final momentum of the ball A = 0.05(–6) = –0.3 kg m s– 1
Impulse imparted to ball A = change in momentum of ball
A = final momentum - initial momentum = − 0.3 − 0.3 = − 0.6 k g m s − 1
Initial momentum of the ball B = 0.05 × ( − 6 ) = − 0.3 k g m s − 1
Final momentum of the ballB = 0.05 × ( 6 ) = 0.3 k g m s − 1
Impulse imparted due toB = 0.3 − ( − 0.3 ) = 0.6 k g m s − 1
Impulse on each ball is 0.6k g m s − 1 in magnitude but these two impulses are opposite in direction.
Initial momentum of the ball A = 0.05 × (6) = 0.3 kg m s
Final momentum of the ball A = 0.05(–6) = –0.3 kg m s
Impulse imparted to ball A = change in momentum of ball
Initial momentum of the ball
Final momentum of the ball
Impulse imparted due to
Impulse on each ball is 0.6
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