Motion in a Plane

Question : 16

Total: 32

A cricketer can throw a ball to a maximum horizontal distance of 100 m. How much high above the ground can the cricketer throw the same ball?

Solution:

Here, Rmax=100m
Now, Rmax=

or u=√Rmax×g or u=√100gms−1
For vertical motion :
Initial velocity, u=√100g; final velocity, v=0
acceleration, a=−g
Now, v2−u2=2aS
If H is the maximum height attained, then
(0)2−(√100g)2=2(−g)H or 2gH=100g or H=

100g

=50m

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