Oscillations

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Question : 4
Total: 25
Which of the following functions of time represent (a) simple harmonic, (b) periodic but not simple harmonic, and (c) non- periodic motion? Give period for each case of periodic motion (ω is any positive constant):
(a) sinωtcosωt
(b) sin3ωt
(c) 3 cos(π42ωt )
(d) cosωt+cos3ωt+cos5ωt
(e) exp(ω2t2)
(f) 1+ωt+ω2t2
Solution:  
The function will represent a periodic motion, if it is identically repeated after a fixed interval of time and will represent simple harmonic motion, if it can be written uniquely in the form of a cos(
2π
T
t
+ϕ
)
or sin(
2π
T
t
+ϕ
)
whereT is the time period.
(a) sinωtcosωt
=2(
1
2
sin
ω
t
1
2
cos
ω
t
)

=2(sinωtcos
π
4
cosωtsin
π
4
)

=2sin(ωt
π
4
)

∴ It represents simple harmonicwith aperiod T=
2π
ω
and a phase angle (
π
4
)
.

(b) sin3ωt=
1
4
(3sinωtsin3ωt)

It represents periodic but not simple harmonic motion. Its time period is =
2π
ω
.

(c) 3cos(
π
4
2ωt
)
=3cos(2ωt
π
4
)

It represents simple harmonic and its time period is
2π
2ω
=
π
ω

(d) cosωt+cos3ωt+cos5ωt
It represents periodic but not simple harmonic motion. Its time period is
2π
ω
. It can be noted that each termrepresents a periodic function with a different angular frequency. Since period is the least interval of time after which a function repeats its value, cosωt has a period T=
2π
ω
, cos3ωt has a period
2π
3ω
, cos5ωt has period
2π
5ω
=
T
5
, the last two forms repeat after any integral multiple of their period. Thus each term in the sum repeats itself after T, and hence the sum is a periodic function with a period
2π
ω

(e) exp (ω2t2) : It is an exponential function which decreases monotonically with increasing time and tends to zero as t and thus never repeats itself. Therefore it represents non-periodic motion.
(f) 1+ωt+ω2t2 It represents non-periodic motion (physically unacceptable because the function tends to infinity as t).
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