Systems of Particles and Rotational Motion

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Question : 9
Total: 33
A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.
Solution:  
M = 1800 kg
Let R1 and R2 be the reactions on front and back wheels.
R1+R2=Mg=1800×9.8
Taking moment about C.G.,
R1×1.05=R2×0.75 or R1=
5
7
R2

5
7
R2
+R2
=1800×9.8
or R2=10290N
So force on each back wheel =
10290
2
=5145N

∴ Force on each front wheel =
7350
2
=3675N
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