Work, Power and Energy

Question : 20

Total: 30

A body of mass 0.5 kg travels in a straight line with velocity v=ax3∕2 where a=5m–1∕2s–1. What is the work done by the net force during its displacement from x=0‌to‌x=2 m?

Solution:

Here, Mass of body = 0.5 kg
Velocity v=ax

where a=5m−

s−1
Initial velocity at x=0,v1=5×0=0
Final velocity at x=2,v2=5×2

Work done = Increase in kinetic energy =

×0.5[(5×23∕2)2−0]=50J

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