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NCERT Class XII Chapter
Alternating Current
Questions With Solutions

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Question : 8
Total: 26
Suppose the initial charge on the capacitor given in question 7 is 6 mC. What is the total energy stored in the circuit initially? What is the total energy at later time?
Solution:  
Initial energy on capacitor, UE =
q02
2C
 =
(6×10−3)2
2×30×10−6
 = 0.6 J
Any time total energy in the circuit is constant, hence energy later is 0.6 J.
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