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Question : 10
Total: 18
In accordance with the Bohr’s model, find the quantum number that characterises the earth’s revolution around the sun in an orbit of radius 1.5 × 1011 m with orbital speed 3 × 104ms–1.
(Mass of earth = 6.0 × 1024 kg)
Solution:  
According to Bohr’s quantization condition of angular momentum,
Angular momentum of the earth around the sun,
mvr =
nh
2π
∴ n = 2πm
r
h
=
2×3.14×6.0×1024×1.5×1011×3×104
6.6×10−34
= 2.57 × 1074
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