NCERT Class XII Chapter
Current Electricity
Questions With Solutions
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Question : 20
Total: 24
(a) Given n resistors each of resistance R, how will you combine them to get the
(i) maximum
(ii) minimum effective resistance? What is the ratio of the maximum to minimum resistance?
(b) Given the resistances of 1 Ω, 2 Ω , 3 Ω, how will be combine them to get an equivalent resistance of
(i) (11/3) Ω (ii) (11/5) Ω, (iii) 6 Ω, (iv) (6/11) Ω?
(c) Determine the equivalent resistance of network shown in figure.
(i) maximum
(ii) minimum effective resistance? What is the ratio of the maximum to minimum resistance?
(b) Given the resistances of 1 Ω, 2 Ω , 3 Ω, how will be combine them to get an equivalent resistance of
(i) (11/3) Ω (ii) (11/5) Ω, (iii) 6 Ω, (iv) (6/11) Ω?
(c) Determine the equivalent resistance of network shown in figure.
Solution:
(a) (i) For maximum effective resistance, all the resistors should be joined in series.
R max = R + R + R + ... n or R max = nR
(ii) For minimum effective resistance, all the resistors should be joined in parallel
=
+
+
+ .... n or
=
so R min =
. Now ,
= n 2
(b) All possible combinations with resistances 1 Ω, 2 Ω and 3 Ω are
So, the combinations for the desired results can be selected.
(ii) All the resistances are in series.
So,R eq = R 1 + R 2 + R 3 + R 4 + R 5 = 5R
(ii) For minimum effective resistance, all the resistors should be joined in parallel
(b) All possible combinations with resistances 1 Ω, 2 Ω and 3 Ω are
So, the combinations for the desired results can be selected.
(ii) All the resistances are in series.
So,
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