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NCERT Class XII Chapter
Current Electricity
Questions With Solutions

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Question : 3
Total: 24
(a) Three resistors 1 Ω, 2 Ω, and 3 Ω are combined in series. What is the total resistance of the combination?
(b) If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.
Solution:  
(a) Total resistance of the combination in series, Req = R1+R2+R3
Req = 1 Ω + 2 Ω + 3 Ω = 6 Ω
(b) Current in the circuit, I =
12
6
 = 2 A

In series, same current flows through each resistor.
Now potential drop across 1 Ω,
V1 = IR1 = 2 × 1 = 2 V
Potential drop across 2 Ω
V2 = IR2 = 2 × 2 = 4 V , IR2 = 2 × 2 = 4 V
Potential drop across 3 Ω , V3 = IR3 = 2 × 3 = 6 V
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