NCERT Class XII Chapter
Dual Nature of Radiation and Matter
Questions With Solutions

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Question : 11
Total: 37
Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.
Solution:  
Energy of incident radiation
E =
hc
λ
=
6.63×1034×3×108
488×109×1.6×1019
eV = 2.55 eV
Now using Einstein’s relation, E = W0 + eV0
where V0 is stopping potential, 2.55 eV = W0 + e × 0.38 V
W0 = 2.55 – 0.38 ⇒ W0 = 2.17 eV.
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