NCERT Class XII Chapter
Dual Nature of Radiation and Matter
Questions With Solutions

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Question : 13
Total: 37
What is the
(a) momentum,
(b) speed, and
(c) de Broglie wavelength of an electron with kinetic energy of 120 eV.
Solution:  
Kinetic energy of electron = 120 × 1.6 × 10–19 J = 1.92 × 10–17 J
(a) Momentum of electron
p = √2Km = √2×1.92×10−17×9.1×10−31 = 5.91 × 10−24kgms−1
(b) Speed of electron
v = √
2K
m
= √
2×1.92×10−17
9.1×10−31
= 6.5 × 106 m s−1
(c) de-Broglie wavelength associated with electron
λ =
h
p
=
6.63×10−34
5.91×10−24
= 1.122
0
A
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