NCERT Class XII Chapter
Dual Nature of Radiation and Matter
Questions With Solutions

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Question : 13
Total: 37
What is the
(a) momentum,
(b) speed, and
(c) de Broglie wavelength of an electron with kinetic energy of 120 eV.
Solution:  
Kinetic energy of electron = 120 × 1.6 × 1019 J = 1.92 × 1017 J
(a) Momentum of electron
p = 2Km = 2×1.92×1017×9.1×1031 = 5.91 × 1024kgms1
(b) Speed of electron
v =
2K
m
=
2×1.92×1017
9.1×1031
= 6.5 × 106 m s1
(c) de-Broglie wavelength associated with electron
λ =
h
p
=
6.63×1034
5.91×1024
= 1.122
0
A
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