NCERT Class XII Chapter
Dual Nature of Radiation and Matter
Questions With Solutions
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Question : 13
Total: 37
What is the
(a) momentum,
(b) speed, and
(c) de Broglie wavelength of an electron with kinetic energy of 120 eV.
(a) momentum,
(b) speed, and
(c) de Broglie wavelength of an electron with kinetic energy of 120 eV.
Solution:
Kinetic energy of electron = 120 × 1.6 × 10 – 19 J = 1.92 × 10 – 17 J
(a) Momentum of electron
p =√ 2 K m = √ 2 × 1.92 × 10 − 17 × 9.1 × 10 − 31 = 5.91 × 10 − 24 k g m s − 1
(b) Speed of electron
v =√
= √
= 6.5 × 10 6 m s − 1
(c) de-Broglie wavelength associated with electron
λ =
=
= 1.122
(a) Momentum of electron
p =
(b) Speed of electron
v =
(c) de-Broglie wavelength associated with electron
λ =
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