NCERT Class XII Chapter
Dual Nature of Radiation and Matter
Questions With Solutions

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Question : 17
Total: 37
(a) For what kinetic energy of a neutron will the associated de Broglie wavelength be 1.40 × 1010 m?
(b) Also find the de Broglie wavelength of a neutron, in thermal equilibrium with matter having an average kinetic energy of
3
2
kT at 300 K.
Solution:  
(a) de Broglie wavelength, λ =
h
2mK

∴ Kinetic energy (K) of neutron
K =
h2
2mλ2
=
(6.63×1034)2
2×1.677×1027×(1.40×1010)2
= 6.686 × 1021 J
=
6.686×1021
1.6×1019
eV = 4.178 × 102 eV
(b) K =
3
2
kT, where k = Boltzmann constant
∴ λ =
h
2mK
=
h
3mkT

=
6.63×1034
3×1.677×1027×1.38×1023×300
m =
6.63×1010
20.8
=
6.63×1010
4.56
m = 1.45 × 1010 = 0.145 nm
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