NCERT Class XII Chapter
Dual Nature of Radiation and Matter
Questions With Solutions

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Question : 6
Total: 37
In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 1015 V s. Calculate the value of Planck’s constant.
Solution:  
Given, slope of graph = 4.12 × 10–15 V s
slope =
h
e

4.12 × 1015 =
h
1.6×1019
or h = 6.592 × 1034 J s
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