NCERT Class XII Chapter
Dual Nature of Radiation and Matter
Questions With Solutions

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Question : 9
Total: 37
The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?
Solution:  
Let us calculate the energy associated with photons incident
E =
hc
λ
=
6.63×1034×3×108
330×109
= 6.027 × 1019 J
E =
6.027×1019
1.6×1019
eV = 3.77 eV
Since, energy of incident photons i.e., 3.77 eV is less than work function, hence no emission will take place.
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