NCERT Class XII Chapter
Electrostatic Potential and Capacitance
Questions With Solutions
© examsnet.com
Question : 23
Total: 37
An electrical technician requires a capacitance of 2 μF in a circuit across a potential difference of 1 kV. A large number of 1 μF capacitors are available to him each of which can withstand a potential difference of not more than 400 V. Suggest a possible arrangement that requires the minimum number of capacitors.
Solution:
Minimum number of capacitors that must be connected in series in a row are
n =
capacitance of 3 capacitors in series in a row is
C' =
Minimum number of rows of 3 capacitors each to be connected in parallel to obtain net capacitance of 2 µF are
m =
So minimum number of capacitors required are m × n = 6 × 3 = 18
n =
capacitance of 3 capacitors in series in a row is
C' =
Minimum number of rows of 3 capacitors each to be connected in parallel to obtain net capacitance of 2 µF are
m =
So minimum number of capacitors required are m × n = 6 × 3 = 18
© examsnet.com
Go to Question: