NCERT Class XII Chapter
Electrostatic Potential and Capacitance
Questions With Solutions
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Question : 26
Total: 37
The plates of a parallel plate capacitor have an area of 90 c m 2 each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply
(a) How much electrostatic energy is stored by the capacitor?
(b) View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume u. Hence arrive at a relation between u and the magnitude of electric field E between the plates.
(a) How much electrostatic energy is stored by the capacitor?
(b) View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume u. Hence arrive at a relation between u and the magnitude of electric field E between the plates.
Solution:
A = 90 c m 2 = 90 × 10 − 4 m 2 , d = 2.5 mm = .5 × 10 − 3 m
C =
=
or C = 32 pF
(a) U =
C V 2 =
× 32 × 10 − 12 × 400 2 or UI = 2.56 µJ
(b) V = A × d = 2.25 ×10 − 4 m 3 =
=
= 0.113 J/m 3
U =
C V 2 =
×
× ( E . d ) 2 =
ε 0 A E 2 d or
=
ε 0 E 2
or Energy per unit volume u =
ε 0 E 2
C =
(a) U =
(b) V = A × d = 2.25 ×
U =
or Energy per unit volume u =
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