NCERT Class XII Chapter
Magnetism and Matter
Questions With Solutions
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Question : 23
Total: 25
A sample of paramagnetic salt contains 2.0 × 10 24 atomic dipoles each of dipole moment 1.5 × 10 – 23 J T – 1 . The sample is placed under a homogeneous magnetic field of 0.64 T, and cooled to a temperature of 4.2 K. The degree of magnetic saturation achieved is equal to 15%. What is the total dipole moment of the sample for a magnetic field of 0.98 T and a temperature of 2.8 K? (Assume Curie’s law)
Solution:
Dipole moment at complete saturation
M = 2 ×10 24 × 1.5 × 10 – 23 = 30 J T – 1
At 0.84 T and 4.2 K, 15% of sample is magnetised
M = C
0.15 × 30 = C
... (i)
At 0.98 T and 2.8 K
M = C
Dividing (i) by (ii), M = 7.875 JT – 1
M = 2 ×
At 0.84 T and 4.2 K, 15% of sample is magnetised
M = C
0.15 × 30 = C
At 0.98 T and 2.8 K
M = C
Dividing (i) by (ii), M = 7.875 J
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