NCERT Class XII Chapter
Moving Charges and Magnetism
Questions With Solutions

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Question : 9
Total: 28
A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30° with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque experienced by the coil?
Solution:  

Torque experienced by the coil carrying current in the given magnetic field.
τ = NIAB sinθ
τ = 20 × 12 × [100 × 104] × 0.8 sin 30°
or τ = 0.96 N m.
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