NCERT Class XII Chapter
Nuclei
Questions With Solutions

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Question : 18
Total: 31
A 1000 MW fission reactor consumes half of its fuel in 5.00 y. How much
235
92
U
did it contain initially? Assume that the reactor operates 80% of the time and that all the energy generated arises from the fission of
235
92
U
and that this nuclide is consumed by the fission process.
Solution:  
In the fission of one nucleus of
235
92
U
, energy generated is 200 MeV.
Energy generated in fission of 1 kg of
235
92
U

= 200 ×
6.023×1023
235
× 1000 N = 5.106 × 1026 MeV
= 5.106 × 1026 × 1.6 × 1013 J = 8.17 × 1013 J
Time for which reactor operates =
80
100
× 5 yr 4 yr.
Total energy generated in 5 year = 1000 × 106 × 60 × 60 × 24 × 365 × 4 J
∴ Amount of
235
92
U
consumed in 5 years
=
1000×106×60×60×24×365×4
8.17×1013
Kg = 1544 kg
∴ Initial amount of
235
92
U
= 2 × 1544 kg = 3088 kg
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