NCERT Class XII Chapter
Nuclei
Questions With Solutions
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Question : 24
Total: 31
The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energies of the nuclei
C a
A l
m(
C a ) (
C a )
m(
A l ) (
A l ) m n
m
m
Solution:
Neutron separation of
C a
E = Energy equivalent of total mass afterward – Energy equivalent of nucleus before
E ={ m (
C a ) + m n − m (
C a ) } c 2
E = {39.962591 + 1.008665 – 40.962278} 931.5 MeV
E = 0.008978 × 931.5 MeV = 8.363 MeV
Similarly, neutron separation energy of
A l
E = [Energy equivalent of
A l
A l
E =[ m 26 ( A l ) + m n − m 27 ( A l ) ] c 2
E = [25.986895 + 1.008665 – 26.981541] 931.5 MeV
E = 0.014079 × 931.5 MeV = 13.058 MeV
E = Energy equivalent of total mass afterward – Energy equivalent of nucleus before
E =
E = {39.962591 + 1.008665 – 40.962278} 931.5 MeV
E = 0.008978 × 931.5 MeV = 8.363 MeV
Similarly, neutron separation energy of
E = [Energy equivalent of
E =
E = [25.986895 + 1.008665 – 26.981541] 931.5 MeV
E = 0.014079 × 931.5 MeV = 13.058 MeV
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