NCERT Class XII Chapter
Nuclei
Questions With Solutions

© examsnet.com
Question : 30
Total: 31
Calculate and compare the energy released by (a) fusion of 1.0 kg of hydrogen deep within the Sun and (b) the fission of 1.0 kg of
235
U
in a fission reactor.
Solution:  
(a) In the fusion reactions taking place within core of sun, 4 hydrogen nuclei combines to form a helium nucleus with the release of 26 MeV of energy.
4
1
1
H
4
2
He
+2e+
+ 26 MeV
Number of atoms in 1 kg of
1
1
H
,
n =
1000g×6×1023
Atomicmass
=
1000g
1g
× 6 × 1023 = 6 × 1026 atoms
Energy released in the fusion of 1 kg of
1
1
H,
E1 =
6×1026×26
4
MeV = 39 × 1026 MeV
(b) Energy released per fission of U-235 is 200 MeV.
Number of atoms in 1 kg of U-235,
n =
1000g×6×1023
235g
= 25.53 × 1023 atoms
Total energy released for fission of 1 kg of uranium,
E2 = 25.53 × 1023 × 200 MeV = 5.1 × 1026 MeV
E1
E2
=
39×1026
5.1×1026
= 7.65 = 8
So the energy released in fusion of 1 kg of Hydrogen is nearly 8 times the energy released in fission of 1 kg of uranium-235.
© examsnet.com
Go to Question: