Object of size 3 cm is placed 14 cm in front of concave lens.
Lens formula,

1

v

−

1

u

=

1

f

1

v

−

1

−14

=

1

−21

1

v

= -

1

21

-

1

14

=

−2−3

42

v = -

42

5

= - 8.4 cm
Formula for magnification
m =

I

O

= +

v

u

or

I

O

=

v

u

or

I

+3

=

−8.4

−14

⇒ I = + 1.8 cm
So, the image is virtual, erect, of the size 1.8 cm and is located 8.4 cm from the lens on the same side as object.
As the object is moved away from the lens, the virtual image moves towards the focus of the lens but never beyond it. The image also reduces in size as shift towards focus.