NCERT Class XII Chapter
Semiconductor Electronics
Questions With Solutions
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Question : 13
Total: 19
In an intrinsic semiconductor the energy gap E g is 1.2 eV. Its hole mobility is much smaller than electron mobility and independent of temperature. What is the ratio between conductivity at 600 K and that at 300 K? Assume that the temperature dependence of intrinsic carrier concentration n i is given by n i = n 0 exp ( −
) , where n 0 is a constant.
k B = 8.62 × 10 − 5 eV K − 1
Solution:
Conductivity is given by
σ = e (n e µ e + n h µ h )
For intrinsic semiconductorn e = n h = n i
Also mobility of holes (µ h ) << mobility of electrons (µ e )
So, conductivity σ =e n e µ e
Temperature dependence of intrinsic carrier concentration
n i = n 0 e ( −
)
So, conductivity, σ =e n i µ e = e µ e n 0 e ( −
)
wheree µ e n 0 = constant σ 0
Hence , σ =σ 0 e ( −
)
Conductivity at 600 K,σ 1 = σ 0 e (
) ... (i)
Conductivity at 300 K,σ 2 = σ 0 e (
) ... (ii)
Dividing (i) and (ii)
= e − [
−
] = e +
[
] or
= e 11.6 = 1 × 10 5
So,σ ( 600 K ) = 10 5 σ ( 300 K )
Conductivity increases rapidly with the rise of temperature.
σ = e (
For intrinsic semiconductor
Also mobility of holes (
So, conductivity σ =
Temperature dependence of intrinsic carrier concentration
So, conductivity, σ =
where
Hence , σ =
Conductivity at 600 K,
Conductivity at 300 K,
Dividing (i) and (ii)
So,
Conductivity increases rapidly with the rise of temperature.
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