NCERT Class XII Chapter
Semiconductor Electronics
Questions With Solutions

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Question : 13
Total: 19
In an intrinsic semiconductor the energy gap Eg is 1.2 eV. Its hole mobility is much smaller than electron mobility and independent of temperature. What is the ratio between conductivity at 600 K and that at 300 K? Assume that the temperature dependence of intrinsic carrier concentration ni is given by ni = n0 exp (
Eg
2kBT
)
, where n0 is a constant.
kB = 8.62 × 105 eV K1
Solution:  
Conductivity is given by
σ = e (neµe+nhµh)
For intrinsic semiconductor ne = nh = ni
Also mobility of holes (µh) << mobility of electrons (µe)
So, conductivity σ = eneµe
Temperature dependence of intrinsic carrier concentration
ni = n0e(
Eg
2kBT
)

So, conductivity, σ = eniµe = eµen0e(
Eg
2kBT
)

where eµen0 = constant σ0
Hence , σ = σ0e(
Eg
2kBT
)

Conductivity at 600 K, σ1 = σ0e(
1.2eV
2kB(600)
)
... (i)
Conductivity at 300 K, σ2 = σ0e(
1.2eV
2kB(600)
)
... (ii)
Dividing (i) and (ii)
σ1
σ2
= e[
0.6eV
600kB
0.6eV
300kB
]
= e+
0.6
8.62×105
[
1
600
]
or
σ1
σ2
= e11.6 = 1 × 105
So, σ(600K) = 105 σ(300K)
Conductivity increases rapidly with the rise of temperature.
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