NCERT Class XII Chemistry
Chapter - Chemical Kinetics
Questions with Solutions

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Question : 30
Total: 39
The rate of a reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation of the reaction assuming that it does not change with temperature.
Solution:  
Given r2=4r1,
T1=293,T2=313 K,Ea=?
We know,
r2
r1
=
k2
k1
=
4
1

Using Arrhenius equation,
log
k2
k1
=
Ea
2.303R
(
1
T1
1
T2
)

log4=
Ea
2.303×8.314
( 1293
1
313
)

or, Ea=log4×
2.303×8.314×293×313
20

or, Ea=52.864 kJ
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