NCERT Class XII Chemistry
Chapter - Chemical Kinetics
Questions with Solutions

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Question : 38
Total: 39
The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea.
Solution:  
Given :T1=298 K,T2=308 K,
Ea=?,r1=r
( say ) then r2=2r
Using Arrhenius equation log
k2
k1
=
Ea
2.303R
[
1
T1
1
T2
]

Putting the values log
2
1
=
Ea
2.303×8.314
[
1
298
1
308
]

0.3010=
Ea
2.303×8.314
[
10
298×308
]

or,
Ea=
0.3010×2.303×8.314×298×308
10
or, Ea=52.897 kJmol1
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