NCERT Class XII Chemistry
Chapter - Coordination Compounds
Questions with Solutions
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Question : 24
Total: 43
Write down the IUPAC name for each of the following complexes and indicate the oxidation state, electronic configuration and coordination number. Also give stereochemistry and magnetic moment of the complex :
(i)K [ C r ( H 2 O ) 2 ( C 2 O 4 ) 2 ] .3 H 2 O
(ii)[ C o ( N H 3 ) 5 C l ] C l 2
(iii)C r C l 3 ( p y ) 3
(iv)C s [ F e C l 4 ]
(v)K 4 [ M n ( C N ) 6 ]
(i)
(ii)
(iii)
(iv)
(v)
Solution:
(i) K [ C r ( H 2 O ) 2 ( C 2 O 4 ) 2 ] .3 H 2 O : Potassiumdiaquadioxalatochromate(III) hydrate
Oxidation state = +3; C.N. = 6; configuration = t3 2 g µ = √ n ( n + 2 )
= √ 3 × 5
= √ 15
= 3.87 B . M .
(ii)[ C o ( N H 3 ) 5 C l ] C l 2 : Pentaamminechloridocobalt(III) chloride
C o ( 27 ) : 4 s 2 3 d 7 ; C o 3 + : 4 s 0 3 d 6
C.N. = 6; Configuration = t6 2 g ; µ = 0 B.M.
(iv)C s [ F e C l 4 ] : Trichloridotripyridinechromium (III) Coordination No. of Cr = 6; Oxidation state = +3; Configuration = t3 2 g ;
C r ( 24 ) : 4 s 1 3 d 5 ; C r 3 + : 4 s 0 3 d 3 µ = √ n ( n + 2 )
= √ 15
= 3.87 B . M .
(iv)C s [ F e C l 4 ] : Caesiumtetrachloridoferrate III)Oxidation state = +3; Coordination No. = 4; Configuration = t3 2 g e2 g
Fe( 26 ) : 4 s 2 3 d 6 ; F e 3 + : 4 s 0 3 d 5
µ = √ n ( n + 2 )
= √ 5 × 7
= √ 35
= 5.92 B . M . ;
(v)K 4 [ M n ( C N ) 6 ] : Potassium hexacyanomanganese(II)Oxidation state = +2; Coordination no. = 6; Configuration = t 2 g 5 ;
Mn(25): [ A r ] 4 s 2 3 d 5 ; M n 2 + : [ A r ] 4 s 0 3 d 5 µ = √ n ( n + 2 )
= √ √ 1 × 3
= 1.732 B . M .
Oxidation state = +3; C.N. = 6; configuration = t
(ii)
The oxidation state of Co = +3
C.N. = 6; Configuration = t
(iv)
(iv)
Fe
It is paramagnetic due to presence of 5 unpaired electrons.
(v)
Mn(25)
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