NCERT Class XII Chemistry
Chapter - Electrochemistry
Questions with Solutions

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Question : 18
Total: 32
Predict the product of electrolysis in each of the following:
(i) An aqueous solution of AgNO3 with silver electrodes.
(ii) an aqueous solution of AgNO3 with platinum electrodes.
(iii) A dilute solution of H2SO4 with platinum electrodes.
(iv) An aqueous solution of CuCl2 with platinum electrodes.
Solution:  
(i) Electrolysis of aqueous solution of AgNO3 with silverelectrodes,
AgNO3(s)+aq Ag+(aq)+NO3(aq)
H2OH++OH
At cathode: Ag+ions have lower discharge potential than H+ions. Hence,Ag+ions will be deposited as Ag in preference to H+ions.
At anode: As Ag anode is attacked by NO3 ions, Ag of the anode willdissolve to form Ag+ions in the solution.
Ag Ag++e
(ii) Electrolysis of aqueous solution of AgNO3using platinum electrodes,
At cathode: Ag will be deposited.
At anode: As anode is not attacked, out of OHand NO3 ions, OHionshave lower discharge potential. Hence, OHions will be discharged inpreference to NO3 ions, and OHwill then decompose to give out O2.
OH(aq) OH+e,
4OH 2H2O(l)+O2(g)
(iii) Electrolysis of dilute H2SO4 with platinum electrodes,
H2SO4(aq)2H+(aq)+SO24(aq)
H2OH++OH
At cathode:H++e H,
H+H H2(g)
At anode: OH OH+e,
4OH 2H2O+O2(g)
Thus, H2 is liberated at the cathode and O2 at the anode.
(iv) Electrolysis of aqueous solution of CuCl2 with platinum electrodes,
CuCl2(s)+aq Cu2+(aq)+2Cl(aq)
H2OH++OH
At cathode: Cu2+ ions will be reduced in preference to H+ions.
Cu2++2e Cu
At anode: Clions will be oxidized in preference to OHions.
Cl Cl+e,
Cl+Cl Cl2(g)
Thus, Cu will be deposited on the cathode and Cl2 will be liberated at theanode.
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