NCERT Class XII Chemistry
Chapter - Electrochemistry
Questions with Solutions

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Question : 8
Total: 32
The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm1. Calculate its molar conductivity.
Solution:  
Given κ=2.48×102 W1cm1,
M=0.20 mol L1
λm=
κ×1000
M

=
1000×2.48×102
0.20

=124Ω1 cm2mol1
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