Test Index

NCERT Class XII Chemistry
Chapter - Solutions
Questions with Solutions

© examsnet.com
Question : 30
Total: 53
Calculate the amount of benzoic acid (C6H5COOH) required for preparing 250 mL of 0.15 M solution in methanol.
Solution:  
M=
w2×1000
M2×V

⇒0.15=
w2×1000
122×250

or, w2=
1.5×122
4
=4.57g
© examsnet.com
Go to Question:
Prev Question
Next Question