NCERT Class XII Chemistry
Chapter - Solutions
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Question : 39
Total: 53
The air is a mixture of a number of gases. The major components are oxygen and nitrogen with approximate proportion of 20% and 79% by volume at 298 K. The water is in equilibrium with air at a pressure of 10 atm. At 298 K, if the Henry’s law constantsfor oxygen and nitrogen are 3.30×107 mm Hg and 6.51×107 mm Hg respectively, calculate the composition of these gases in water.
Solution:  
Total pressure of air in equilibrium with water = 10 atmosphere
As air contains 20% oxygen and 79% nitrogen by volume,
Partial pressure of oxygen (pO2)=
20
100
×10
atm
= 2 atm = 2 × 760 mm Hg = 1520 mm Hg
Partial pressure of nitrogen (pN2)=
79
100
×10
atm
= 7.9 atm = 7.9 × 760 mm Hg = 6004 mm Hg
KH(O2)=3.30×107 mm Hg, KH(N2)=6.51×107 mm Hg
Applying Henry’s law ,pO2=KH×xO2
or, xO2=
pO2
KH
=
1520mmHg
3.30×107mmHg
=4.61×105

pN2=KH×xN2
xN2=
pN2
KH
=
6004mmHg
6.51×107mmHg
=9.22×105
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