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NCERT Class XII Chemistry
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Question : 40
Total: 53
Determine the amount of CaCl‌2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27°C.
Solution:  
From the expression, π=i
n
V
RT
or, n=
π×V
i×R×T
=
0.75atm×2.5 L
2.47×0.0821 L atm K−1 mol−1 ×300 K
=0.0308 mole
Molar mass of CaCl2=40+2×35.5
=111 g mol−1
∴‌ Amount of CaCl2 dissolved =0.0308×111
=3.42 g
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