NCERT Class XII Chemistry
Chapter - Solutions
Questions with Solutions

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Question : 53
Total: 53
Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.
Solution:  
Given, Number of moles of solute dissolved (n)
=
1.0g
185,000 g mol1

=
1
185,000
mol

V=450 mL=0.450 L,
T=370 C
=37+273=310 K R =8.314 kPa L K1 mol1
=8.314×103Pa L K1 mol1
pi=CRT=
n
V
R
T

Substituting these values, we get
π=
1
185,000
×
1
0.45
×8.314
×103
×310

=30.96 Pa
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