(i) Structure of ICl–4 : I‌in‌ICl–4 has four bond pairs and two lonepairs. Therefore, according to VSEPR theory, it should be square planaras shown.
Here, ICl–4 has (7 + 4 × 7 + 1) = 36 valence electrons. A noblegas specieshaving 36 valence electrons is
XeF‌4(8 + 4 × 7 = 36). Therefore, like ICl–4 , XeF‌4 is also square planar.
(ii) Structure of IBr–2 :I in IBr–2 has two bond pairs and three lone pairs.So,according to VSEPR theory, it should be linear.Here,IBr–2 has 22 (7 + 2 × 7 + 1) valence electrons.A noble gas species having 22 valence electrons is XeF‌2 (8 + 2 × 7 = 22).Thus, like IBr–2 , XeF‌2 is also linear :(iii)Structure of BrO–3: The central atom Br has seven electrons. Four ofthese electrons form two double bonds or coordinate bonds with twooxygen atoms while the fifth electron forms a singlebond with O‌–ion.The remaining two electrons form one lone pair. Hence, in all there arethree bond pairs and one lone pair around Br atom in BrO–3. Therefore,according to VSEPR theory, BrO–3should be pyramidal.
Here,BrO–3has26(7 + 3 × 6 + 1 = 26) valence electrons. A noble gas specieshaving 26 valence electrons is XeO3(8 + 3 × 6 = 26). Thus, like BrO–3 , XeO3is also pyramidal.