NCERT Class XII Mathematics Chapter - - Solutions
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Question : 24
Total: 101
Given that the events A and B are such that P ( A ) =
P ( A ∪ B ) =
Solution:
(i) When A and B are mutually exclusive, then
A ∩ B = ϕ ⇒ P(A ∩ B) = 0
⇒ P(A ∪ B) = P(A) + P(B)
⇒
=
+ p
⇒ p =
.
(ii) When A and B are independent, then P(A ∩ B) = P(A) P(B)
⇒ P(A ∪ B) = P(A) + P(B) – P(A) P(B)
⇒
=
+ p −
p
⇒ p =
.
A ∩ B = ϕ ⇒ P(A ∩ B) = 0
⇒ P(A ∪ B) = P(A) + P(B)
(ii) When A and B are independent, then P(A ∩ B) = P(A) P(B)
⇒ P(A ∪ B) = P(A) + P(B) – P(A) P(B)
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