NCERT Class XII Mathematics Chapter - - Solutions

© examsnet.com
Question : 60
Total: 101
Find the mean number of heads in three tosses of a fair coin.
Solution:  
Sample space = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}.
Let X denotes the random variable, which represents the number of heads in three tosses of a fair coin.
∴ X can assumes values 0, 1, 2 and 3.
P(X=0)=
1
8
, P(X=1)=
3
8
, P(X=2)=
3
8
and P(X=3)=
1
8
.Hence the probability distribution :
 X  0  1  2  3
  P(X)  
1
8
 
3
8
 
3
8
 
1
8
∴ Mean = E(X) = ∑X P(X)
=(0×
1
8
)
+(1×
3
8
)
+(2×
3
8
)
+(3×
1
8
)
=
3
2
© examsnet.com
Go to Question: