AFCAT Model Paper 10

Given: Alloy A contains metals gold and bronze in the ratio 5 : 8 Alloy B contains these metals in the ratio 3 : 10 Alloy C is prepared by mixing A and B in the ratio 1 : 1 Calculations: Alloy A ⇒ gold = 5/13, bronze = 8/13Alloy B⇒ gold $= \frac{3}{13}$ , bronze $= \frac{10}{13}$ ⇒ gold $= \left(\frac{5}{13}\right) + \left(\frac{3}{13}\right) = \frac{8}{13}$ ⇒ bronze $= \left(\frac{8}{13}\right) + \left(\frac{10}{13}\right) = \frac{18}{13}$ ⇒ Ratio of gold to bronze $= \frac{8}{13} : \frac{18}{13}$ ⇒ 8 : 18 ⇒ Ratio of bronze to gold = 9 : 4 ∴ Ratio of bronze to gold is 9 : 4.