Given: The ratio of milk and water in the original mixture = 4 : 1
10 liters of this mixture is replaced by 10 liters of water
The ratio of milk and water in the resultant mixture = 2 : 3
Calculation: Let the volume of water be x
⇒ The volume of milk = 4x
Now, According to the question
⇒ Volume of milk replaced
=()×10= $$ 8 liters
⇒ Volume of water replaced = 10 – 8 = 2 liters
Again, According to the question,
= ⇒ 12x – 24 = 2x + 16
⇒ 10x = 24 + 16
⇒x==4 ⇒ Volume of milk initially = 4 × 4 = 16 liters
∴ The initial volume of milk is 16 liters.