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AIEEE 2010 Solved Paper
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© examsnet.com
Question : 40
Total: 89
The equation of a wave on a string of linear mass density
0.04
kg
m
−
1
is given by
y
=
0.02
(
m
)
s
i
n
[
2
π
(
t
0.04
(
s
)
−
x
0.50
(
m
)
)
]
.
The tension in the string is
4.0
N
12.5
N
0.5
N
6.25
N
Validate
Solution:
y
=
0.02
(
m
)
s
i
n
[
2
π
(
t
0.04
(
s
)
)
−
x
0.50
(
m
)
]
But
y
=
a
s
i
n
(
ω
t
−
k
x
)
∴
ω
=
2
π
0.04
⇒
v
=
1
0.04
=
25
Hz
k
=
2
π
0.50
⇒
λ
=
0.5
m
∴
velocity,
v
=
v
λ
=
25
×
0.5
m
/
s
=
12.5
m
/
s
Velocity on a string is given by
v
=
√
T
µ
∴
T
=
v
2
×
µ
=
(
12.5
)
2
×
0.04
=
6.25
N
© examsnet.com
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