Heat required to melt 1 g of ice at 0°C to water at 0°C = 1×80 cal. Heat required to raise temperature of 1 g of water from 0°C to 100°C = 1×1×100=100 cal. total heat required for maximum temperature of 100°C = 80+100=180 cal. As one gram of steam gives 540 cal of heat when it is converted to water at 100°C, therefore, temperature of the mixture = 100°C.