Given that, 4x2−24xy+11y2=0 On comparing with ax2+2hxy+by2=0, we get a=4,b=11 and h=−12 ∴ using h2−ab=(−12)2−4×11 =144−44=100 ∴ The two lines represented by given equation will be real and distinct which represent a pair of straight lines passing through the origin.