Given equation of hyperbola is x2−3y2=3 therefore Equation of tangent at point (√3,0) is S1=0 ⇒x√3−3y×0=3 ⇒ x√3=3 ⇒ x=√3 ......(i) The asympotes of given hyperbolas are x+√3y=0 .......(ii) and x−√3y=0 .......(iii) On solving Eqs. (i), (ii) and (iii), we get (0,0),(√3,−1)and (√3,1) ∴ Area of triangle formed by joining the above points =