Case I When smaller of the two numbers is 1. Then, total number of cases =1×7C1=7 Case II When smaller of two numbers is 2. Then, total number of cases =1×6C1=6 Case III When smaller of two numbers is 3. Then, total number of cases =1×5C1=5 Total favourable cases =7+6+5=18 Total case =8C2=28 ∴ Required probability =